Combination of aluminum and stainless steel

[davehetfield]

Original post edited to a SPAM post

[Vadim Verlotski]

The stresses that arise in the junction of two metals depend not only on the difference in their thermal expansion coefficients. If we write down Hooke's law for these stresses, then it will look like this:
σ1 = E1ΔTΔα, where σ1 is the stress in one of the layers, E1 is the elastic modulus of this layer, ΔT is the temperature difference, Δα is the difference in the coefficients of linear thermal expansion.
Since the modulus of elasticity of aluminum is relatively small, and the softening temperature is low (there simply cannot be a large ΔT due to the transition of the material into a plastic state), the resulting stresses are also small. In addition, the difference in linear thermal coefficients between austhenic stainless steels (α = 17-18 x10-6K-1) and aluminum alloys (α = 20-23 x 10-6K-1) is not at all that significant.

[Vadim Verlotski]

-