Posted by ELLIS AGBEKO on March 07, 2004 at 09:30:15:
In Reply to: Re: Weatherproof coating of odd-shaped parts posted by John on March 01, 2004 at 11:24:57:
: : : I work for a manufacturing company where we have our own in-house electrodeposition coating department, i.e. we coat all our hardware with anti-corrosion liquid. We have some parts that are of extremely odd shapes. Determining the surface area of these parts, and consequently, determining the total square footage of these parts and the amount of coating needed has proven to be very difficult. One method I have suggested is to have a container filled with a measured amount of water. The next step is to place the object in the water. The resulting displacement of the water before immersion vs. after immersion would give me the total volume/area of the part. Is this correct? Any help in this matter would be greatly appreciated. Cheers -
: : Hi
: : This will give you the volume of the object, but not the surface area.
: : For example:
: : take 1 cubic inch of material in the form of a solid square cube - surface area = 6 square inches.
: : take 1 cubic inch of material in the form of 0.01 x 10 x 10 sheet - surface area = 200.04 square inches.
: : Sorry, no easy way.
: : Regards Gordon
: The only easy way of working this out for a complicated shape is to draw it out in a cad package and use that to tell you.
: cheers
: john
hi,
Another way could be for you to make a slurry of clay of known density in a container. weigh the contents. measure any regular part of your component. now imerse the component in the slurry, take out and allow to dry. weigh the remaining slurry to know how much has been taken by the component. re-measure the regular part of the component and calculate the thickness of deposition as half the difference in diameter. if you take care of shrinkage you will now be able to calculate the surface area by dividing the difference in weight of slurry by the density and the thicness of slurry coating calculated earlier.
good luck.
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