Posted by John on March 01, 2004 at 11:24:57:
In Reply to: Re: Weatherproof coating of odd-shaped parts posted by gordonengland@hotmail.com on February 13, 2004 at 15:18:21:
: : I work for a manufacturing company where we have our own in-house electrodeposition coating department, i.e. we coat all our hardware with anti-corrosion liquid. We have some parts that are of extremely odd shapes. Determining the surface area of these parts, and consequently, determining the total square footage of these parts and the amount of coating needed has proven to be very difficult. One method I have suggested is to have a container filled with a measured amount of water. The next step is to place the object in the water. The resulting displacement of the water before immersion vs. after immersion would give me the total volume/area of the part. Is this correct? Any help in this matter would be greatly appreciated. Cheers -
: Hi
: This will give you the volume of the object, but not the surface area.
: For example:
: take 1 cubic inch of material in the form of a solid square cube - surface area = 6 square inches.
: take 1 cubic inch of material in the form of 0.01 x 10 x 10 sheet - surface area = 200.04 square inches.
: Sorry, no easy way.
: Regards Gordon
The only easy way of working this out for a complicated shape is to draw it out in a cad package and use that to tell you.
cheers
john
Follow Ups:
Please go to the new Surface Engineering Forum as this old message board is a read only archive. Please copy and paste relevant information or link to this page if you wish to reactivate this thread on the new forum.
